Răspuns:
A(1 ; 0) ; B(2 ; 0)
C(0 ; 2)
Explicație pas cu pas:
f : R --> R
f(x) = x² - 3x +2
f(x) = x²-2x-x+2 = x(x-2)-(x-2) = (x-2)(x-1)
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∩ Ox <=> f(x) = 0 => (x-2)(x-1) = 0 => x₁ = 1 ; x₂ = 2 =>
A(1 ; 0) ; B(2 ; 0)
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∩ Oy <=> x = 0 => f(0) = (0-2)(0-1) = (-2)(-1) = 2 =>
C(0 ; 2)