Răspuns:
AB = BC = √41
Explicație pas cu pas:
[tex]AB=\sqrt{(x_{1}-x_{2})^{2} +(y_{1} -y_{2})^{2} }[/tex]
[tex]AB = \sqrt{(-2-3)^{2}+(1-5)^{2} }[/tex]
[tex]AB = \sqrt{(-5)^{2}+(-4)^{2} } = \sqrt{25+16} =\sqrt{41} ;[/tex]
[tex]BC=\sqrt{(3-7)^{2} +(5-0)^{2} }[/tex]
[tex]BC=\sqrt{(-4)^{2}+5^{2} } = \sqrt{16+25} =\sqrt{41} ;[/tex]
[tex]AC=\sqrt{(-2-7)^{2}+(1-0)^{2} }[/tex]
[tex]AC = \sqrt{(-9)^{2}+1^{2} } =\sqrt{81+1} =\sqrt{82} ;[/tex]
AB = BC ⇒ ΔABC - isoscel.
