Rezolvare:
Amplificăm cu √3
[tex]\dfrac{^{\sqrt{3}) } 6+2\sqrt{3} }{2\sqrt{3} } = \dfrac{(6+2\sqrt{3} ) \cdot \sqrt{3} }{2\sqrt{3} \cdot \sqrt{3} } = \dfrac{6\sqrt{3} +2\sqrt{3} \cdot \sqrt{3} }{2 \cdot 3} =\\[/tex]
[tex]= \dfrac{6\sqrt{3} + 2\cdot3}{6} = \dfrac{6(\sqrt{3} + 1)}{6}^{(6} = \sqrt{3} + 1[/tex]
