[tex]\it a)\ \ 100\%-40\%=60\%\ (reprezint\breve a\ fetele)\\ \\ 60\%\ din\ 30=\dfrac{60}{100}\cdot30=6\cdot3=18\ (Da, este\ posibil)\\ \\ \\ b)\ 30-18=12\ b\breve aie\c{\it t}i\ sunt\ \hat\imath n\ clas\breve a\\ \\ Not\breve am\ cu\ x\ num\breve arul\ b\breve aie\c{\it t}ilor\ care\ ar\ trebui\ s\breve a\ plece.\\ \\ 12-x=\dfrac{\ \ 25^{(25}}{100}\cdot(30-x) \Rightarrow12-x=\dfrac{1}{4}\cdot (30-x)\bigg|_{\cdot4} \Rightarrow[/tex]
[tex]\it \Rightarrow 48-4x=30-x \Rightarrow 48-30=4x-x \Rightarrow 18=3x \Rightarrow x=6[/tex]
