Răspuns:
reactia care are loc
2NaCl------>2Na+ Cl2
calculez nr. moli Cl2 din V= 4,1X10³l
pV=niuRT 1,5X4,1X10³= niux0,082x(273+27)
niu= 250mol Cl2
deduc moli si masa NaClpur ,stiind M,nAcL=58,5g/mol
2mol NaCl.........1molCl2
x.............................250mol
x= niu= 500mol NaClpur
m=niuxM= 500x58,5g=29250g=29,25kgNaCl-teoretic
m,practic va fi mai mare din cauza randamentului
m,practic= 29,25x100/80kg= 36,562kg NaCl pur
calculez masa de sare impura
m,i-=36,562x100/75kg= 48,75kg, deoarece p= m,px100/m,i
Explicație: