[tex]\it a)\ \ \ \dfrac{1}{8}+\dfrac{1}{8}\cdot4=\dfrac{1}{8}\cdot\bigg(1+4\bigg)=\dfrac{1}{8}\cdot5=\dfrac{5}{8}\\ \\ \\ b)\ \ \ \dfrac{1}{6}+\dfrac{1}{6}:\dfrac{1}{3}=\dfrac{1}{6}+\dfrac{1}{6}\cdot\dfrac{3}{1}=\dfrac{1}{6}\bigg(1+3\bigg)=\dfrac{1}{6}\cdot4=\dfrac{\ \ 4^{(2}}{6}=\dfrac{2}{3}\\ \\ \\ c)\ \ \dfrac{4}{9}+\dfrac{3}{10}:\dfrac{6}{10}=\dfrac{4}{9}+\dfrac{3}{10}\cdot\dfrac{10}{6}=\dfrac{4}{9}+\dfrac{\ \ 30^{(30}}{60}=\dfrac{^{2)}4}{\ 9}+\dfrac{^{9)}1}{\ 2}=\dfrac{17}{18}[/tex]
[tex]\it \ \ d)\ \ 1\dfrac{1}{3}\cdot2\dfrac{1}{2}+6=\dfrac{\not4\ ^2}{3}\cdot\dfrac{5}{\not2}+6=\dfrac{10}{3}+6=3\dfrac{1}{3}+6=9\dfrac{1}{3}[/tex]
