Răspuns:
[tex] \sqrt{ \frac{15}{10} } = \sqrt{ \frac{3}{2} } = \frac{ \sqrt{6} }{2} [/tex]
[tex] \sqrt{3 + \frac{3}{8} } = \sqrt{ \frac{27}{8} } = \frac{ 3\sqrt{3} }{2 \sqrt{2} } = \frac{3 \sqrt{6} }{4} [/tex]
[tex] \sqrt{1 + \frac{1}{2} } = \sqrt{ \frac{3}{2} } = \frac{ \sqrt{6} }{2} [/tex]
[tex] \frac{ \sqrt{6} }{2} - \frac{3 \sqrt{6} }{4} - \frac{5}{6} \times \frac{ \sqrt{6} }{2} = \\ \frac{6 \sqrt{6} - 9 \sqrt{6} - 5 \sqrt{6} }{12} = - \frac{8 \sqrt{6} }{12} = - \frac{2 \sqrt{6} }{3} [/tex]
