Răspuns:
A. \( \frac{13}{4} - 5\%3 = \frac{13}{4} - \frac{5}{3} = \frac{13 \cdot 3}{4 \cdot 3} - \frac{5}{3} = \frac{39}{12} - \frac{5}{3} = \frac{39}{12} - \frac{20}{12} = \frac{19}{12} \)
B. \( \left(\frac{9}{4} + \frac{9}{4}\%4\right) \times \frac{5}{2} = \left(\frac{9}{4} + \frac{9}{4}\%4\right) \times \frac{5}{2} = \left(\frac{9}{4} + \frac{9}{4}\right) \times \frac{5}{2} = \frac{9+9}{4} \times \frac{5}{2} = \frac{18}{4} \times \frac{5}{2} = \frac{9}{2} \times \frac{5}{2} = \frac{45}{4} \)
C. \( \frac{((2+4) \times \left(\frac{5}{2} + 1\right) - 3)}{2} = \frac{(6 \times \left(\frac{5}{2} + 1\right) - 3)}{2} = \frac{(6 \times \left(\frac{5+2}{2}\right) - 3)}{2} = \frac{(6 \times \left(\frac{7}{2}\right) - 3)}{2} = \frac{(6 \times \frac{7}{2} - 3)}{2} = \frac{(21 - 3)}{2} = \frac{18}{2} = 9 \)
D. \( 125\% 10+ \left(\frac{125}{10}\right) \% 10+ \left(\frac{125}{100}\right) = 12 + 5 + 1 = 18 \)
