Răspuns:
x = 80 ; y = 96 ; z = 160
Explicație pas cu pas:
2x+3y-2z = 128
x/5 = y/6 = z/10 =>
x = 5y/6
z = 10y/6
2·5y/6 + 3y - 2·10y/6 = 128 <=>
5y/3 + ³⁾3y - 10y/3 = ³⁾128 =>
5y+9y-10y = 384 => 4y = 384 =>
y = 384:4 => y = 96
x = 5·96/6 = 5·16 = > x = 80
z = 10·96/6 = 10·16 => z = 160
2x = 160 ; 3y = 288 ; 2z = 320
2x+3y-2z = 160+288-320 = 128
