Răspuns:
pshzbbahaajdjbjjshhdhhdh
trebuie 30+60=90 drum
[tex]\it 100\%-30\%=70\%\ \ (rest, dup\breve a\ prima\ zi)\\ \\ \\ 60\%\ din\ 70\%=\dfrac{60}{100}\cdot\dfrac{70}{100}=\dfrac{4200}{10000}=\dfrac{42}{100}=42\%\ parcurge\ a \ 2-a\ zi\\ \\ \\ 30\%+42\%=72\%\ din\ traseu,\ \ parcurge\ \ \hat\imath n\ primele\ dou\breve a\ zile\\ \\ \\ 100\%-72\%=28\%\ \ restul\ pentru\ a\ treia\ zi\\ \\ Dac\breve a\ vom\ nota\ lungimea\ traseului\ cu\ t, atunci\ putem\ scrie:[/tex]
[tex]\it 28\%\ din\ t=112 \Rightarrow \dfrac{28}{100}t=112 \Rightarrow t=112\cdot\dfrac{100}{28}=\dfrac{11200}{26}=400\ km[/tex]
