a) aratam ca dT= dt, unde dT este in (⁰K) si dt in (⁰C)
Fie t1 si t2 doua tempetaturi in ⁰C.
Stim ca T1=t1+273, T2=t2+273
dT=T2-T1=(t2+273)-(t1+273)=
t2+273-t1-273=t2-t1=dt
Deci dT=dt
b) tC=(tF-32)/1.8 unde tC este temperatura in ⁰C si tF in ⁰F
1.8×tC=tF-32
Dar 1.8=18/10=9/5
Astfel tF=1.8tC+32=9/5×tC+32
c) tF=0, deci tC=(0-32)/1.8=-32/1.8=-17.78⁰C
d) T(K)=0K
0=273+tC, deci tC=-273⁰C
tF=1.8×tC+32=-1.8×273+32=-459.4⁰F
