Răspuns:
d= M,alchena/M,N2---> M,alchena= 2,5x28g/mol= 70g/mol
M,alchena=M,CnH2n= 14n
14n=70---> n= 5
izomerii sunt 1 pentena, 2 pentena si 2metil 1 butena ,3metil 1 butena , 2 metil 2 butena
Cei 3 izomeri de catena dau prin hidrogenare 2 metil butan
1mol...................................4mol
CH2=-C(CH3)-CH2-CH3+ 4O---> CO2+H2O + O=C(CH3)-CH2-CH3
1mol...................................5mol
CH2=CH-C(CH3)-CH3+ 5O----> CO2+H2O+ HOOC-C(CH3)-CH3
1mol...............................3mol
CH3-C(CH3)=CH-CH3+ 3O===> CH3-C(CH3)=O+ HOOC-CH3
3mol amestec consuma 12molO
din 1mol K2Cr2O7 rezulta........3molO
X......................................................12mol
x=4mol K2Cr2O7
Explicație:
