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va rog ajutor dau coroana ​

Va Rog Ajutor Dau Coroana class=

Răspuns :

Răspuns:

echiunitara

4x-27=3x+5

4x-3x=27+5=32

x=32/4=8

subunitara

4x-27<3x+5

x<27+5=32

x=0,1,.....31

supraunitara

4x-27>3x+5

4x-3x>32

x>32

x=33,34.....+ infinit

întregi

[tex]\it a)\ \dfrac{4x-27}{3x+5} < 1 \Rightarrow4x-27 < 3x+5 \Rightarrow 4x-3x < 5+27 \Rightarrow \\ \\ \\ \Rightarrow x < 32 \Rightarrow x\in\{0,\ \ 1,\ \ 2,\ \ 3,\ \ ...\ \ 31\}\\ \\ \\ b)\ \ \dfrac{4x-27}{3x+5}=1\ \stackrel{a)}{\Longrightarrow}\ x=32\\ \\ \\ c)\ \ \dfrac{4x-27}{3x+5} > 1\ \stackrel{a)}{\Longrightarrow}\ x > 32 \Rightarrow x\in\{33,\ \ 34,\ \ 35,\ \ ...\}[/tex]