[tex]\2x-\sqrt{27}=\sqrt3 \Rightarrow 2x=\sqrt3+\sqrt{27} \Rightarrow 2x=\sqrt3+3\sqrt3 \Rightarrow 2x=4\sqrt3\bigg|_{:2} \Rightarrow x=2\sqrt3\\ \\ \\ x\sqrt{20}-10=x\sqrt{45} \Rightarrow 2\sqrt5x-10=3\sqrt5x \Rightarrow -10=3\sqrt5-2\sqrt5 \Rightarrow -10=\sqrt5x \Rightarrow \\ \\ \Rightarrow x=-\dfrac{^{\sqrt5)}10}{\ \ \sqrt5}=-\dfrac{10\sqrt5}{5}=-2\sqrt5[/tex]
