Aplicam formula lui Galileo Galilei
[tex]v_{final}^2=v_{initial}^2+2*a*h_{max}\\v_{final}=0\\a=-g=-9,8 m/s^2\\v_{initial}=15 m/s\\v_{final}^2=v_{initial}^2+2*a*h_{max} < = > 0^2=15^2-2*9,8*h_{max} < = > 225=19,6h_{max}= > h_{max}=\frac{225}{19,6}= > h_{max}=11,48 m[/tex]
