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f: RR, fcx) = ax + b A(-1; 3) BC-2;0); a-: b-?. ​

Răspuns :

Răspuns:

a = 3

b = 6

Rezolvare:

f : R → R, f(x) = ax + b

A(-1; 3) ∈ Gf ⇔ f(-1) = 3

-a + b = 3

B(-2; 0) ∈ Gf ⇔ f(-2) = 0

-2a + b = 0

[tex]\left \{ {{-a+b=3} \atop {-2a+b=0}} \right. \iff\left \{ {{b=3+a} \atop {-2a+b=0}} \right. \\[/tex]

-2a + 3 + a = 0

-a + 3 = 0

-a = -3

a = 3

b = 3 + a = 3 + 3

b = 6

Succes! ❀

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