5. Se considera AABC si medianele BM si CN, BM CN={G}. Daca BC=7 cm, NG-3 cm si BM-8 cm, calculati perimetrul ABGC.

[tex]\it CG=2\cdot NG=2\cdot3=6\ cm\\ \\ BG=\dfrac{2}{3}\cdot BM=\dfrac{2}{3}\cdot8=\dfrac{16}{3}=5\dfrac{1}{3}\ cm\\ \\ \\ \mathcal{P}_{BGC}=BG+GC+BC=5\dfrac{1}{3}+6+7=18\dfrac{1}{3}\ cm[/tex]