Calculează a) (20+2×(110-2011: 10+2×4= b) [72: (8x2-40:5)+91): (7 + 3) = c) 200+ 30 x 19 x (8+4):4)-880:10- d) 16 x 140+2x (560:8-7x71x(10-100:10) = e) 1000+ 8×[(56:7 +12) × 101-2000):2= 7) 999:9×2+(92+2x4x(29-14x2:7)x9)+5× 20 = p) 592 +8x [(56:7 +13) * 101 - 2076):2 = h) 125:5+17x36:2-5x(5x4-36:3)1 x 10 = 0) 125:5+ [14x18:2-5x(100:5-72:6)] = AJ) (100-7×2×5)×[(282: 3-2): 2) = k) 25 x 4+((2 x 13+54×2×24):2-309):5= 1) 10×[(36×8-40):8+ (2x41-12):51+100= m) 80:20+3×[50+3×(350:7-98:2)]= n) 54 x 10+ [(780:4+76x 10):5+343):6-200 x 3 = o) (29+3x9-13:13-50: (7+3)]:(9-6:3+43)= p) 981:3-(164+ (248:8+4x39+117:9):10] = q) 10 x [64 x 11-12 + (44:4+30:5) x2 +132:41-25×4= Tr) (24:3+15x2+9:3+3): [(72:4+6x12)-15×4-8] = +$) 520:10+ [770:7-(835:5-976:8+495:9):10]: 100-261:9= e) ((25:5+10x10:10) x2 + (88:8 +6-33:3)x2)x(111-101) +1000 Tu) 665:7+ [(15+680:5+1-918:9) x 10]: 100 = v) [(31 024:4+486:9): 10+1219] x 12×(5-30:6) = w)5 x (9x111+74x6)-[(500-112x4)x3-(100-37):7:3]×2= x) 48 x [790:2-(956:2-1-237x2)x128-1]-4x115= y) 1-[4x250-(3+564:3+39-4x55) *99]: 10 = z) [998-455:7+(99 x 63-10x2x13)]: 10+5000:1000 = Ştiind că a = 20 x 25+50x4+10 x 10, iar b= 10 000: 100:10:5, calcule a-b a+b axb a:b a: 100+ bx5 (a+b)x10:2 Dacă a=3x3+2x4x [7+6x (2x 10-3)-2x11-1000:10 şi b=9+ [7+3x (12-7)]:2-5x2, atunci (a + b): 25 este egal cu: a) 310 b) 31 c) 301 d) 135​