Răspuns:
[tex] \frac{1}{e(1)} = \frac{1}{ \frac{1}{1 - 2} } = \frac{1}{ - 1} = - 1 \\ \frac{1}{e(2)} = \frac{1}{ \frac{1}{1 - 4} } = - 3 \\ \frac{1}{e(3)} = \frac{1}{ \frac{1}{1 - 6} } = - 5 \\ \frac{1}{e(100)} = \frac{1}{ \frac{1}{1 -200 } } = - 199[/tex]
-(1 + 3 + 5 + ... + 199) = -(100)^2 = -10000
2n - 1 = 199
2n = 200
n = 100
