[tex]R\breve{a}spuns: \boldsymbol{ \red{ \dfrac{3}{10} }}[/tex]
Rezolvare:
Înlocuim cu a:
[tex]\dfrac{a}{7} = \dfrac{5}{3} \implies a = \dfrac{7 \cdot 5}{3}[/tex]
[tex]\dfrac{5}{a + 5} = \dfrac{5}{\dfrac{35}{3} + 5} = \dfrac{5}{\dfrac{35+15}{3}} = \dfrac{5 \cdot 3^{(5} }{50} = \bf \dfrac{3}{10}[/tex]
***
sau:
[tex]\dfrac{a}{7} = \dfrac{5}{3} = k \implies a = 7k, 5 = 3k[/tex]
[tex]\dfrac{5}{a + 5} = \dfrac{3k}{7k+3k} = \dfrac{3k^{(k} }{10k} = \dfrac{3}{10}[/tex]
