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(0,5)^(x-1)+2^(x+2)=9

Răspuns :

[tex]\( (0,5)^{x-1} + 2^{x+2} = 9 \), \[ (0,5)^{x-1} + 2^{x+2} = 9 \] \( 2^{x+2} \) \( 2^2 \cdot 2^x \)\cdot2^2 = 4 \). \[ (0,5)^{x-1} + 4 \cdot 2^x = 9 \] \( (0,5)^{x-1} \) cu \( 2^{-x+1} \) \[ 2^{-x+1} + 4 \cdot 2^x = 9 \] \( 2^{-x+1} \)\( 4 \cdot 2^x \)[/tex]