Răspuns:
a = 10
Rezolvare:
[tex]a=(2^3-2^2)[3(10^2-3^2\times11)+1^{2020}:1^{1006}]-(6^3-10\times21)=\\[/tex]
[tex]=(2-1)\times2^2\times[3(100-9\times11)+1:1]-(6^3-210)=\\[/tex]
[tex]=1\times2^2\times[3(100-99)+1]-6^3+210=\\[/tex]
[tex]=2^2(3\times1+1)-216+210=\\[/tex]
[tex]=16-216+210\\[/tex]
[tex]\implies \bf\red{\boxed{\boxed{a=10}}}[/tex]
______________
Nu uităm de următoarele formule:
[tex]\bf\purple{\boxed{a^m\times a^n=a^{m+n}}}[/tex]
[tex]\bf\red{\boxed{a^m:a^n=a^{m-n}}}\\[/tex]
Succes! ❀
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