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Rezultatul calcului 3√24+ 2√48- 10√3- √108

Răspuns :

[tex]3\sqrt{24} + 2\sqrt{48} - 10\sqrt{3} - \sqrt{108} =[/tex]

scoatem factori de sub radical:

[tex]= 3\sqrt{4\cdot6} + 2\sqrt{16\cdot3} - 10\sqrt{3} - \sqrt{36\cdot3} =[/tex]

[tex]=3\cdot2\sqrt{6} + 2\cdot4\sqrt{3} - 10\sqrt{3} -6\cdot\sqrt{3} =[/tex]

[tex]=6\sqrt{6} + 8\sqrt{3} - 10\sqrt{3} -6\cdot\sqrt{3} =[/tex]

reducem termenii asemenea:

[tex]=6\sqrt{6} - 8\sqrt{3} =[/tex]

scoatem factor comun:

[tex]\mathbf{=2\sqrt{3}\cdot (3\sqrt{2} - 4)}[/tex]