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(3-√6)(3+√6)+(√3-1)(√3+1)-(3-√5)(3+√5)=
calculati folisind formulele de calcul prescurtat​


Răspuns :

Folosim formula de calcul prescurtat​

[tex]\boxed{\boldsymbol{(a - b)(a + b) = a^{2} - b^{2}}}[/tex]

①  (3-√6)(3+√6) = 3² - (√6)² = 9 - 6 = 3

②  (√3-1)(√3+1) = (√3)² - 1² = 3 - 1 = 2

③  (3-√5)(3+√5) = 3² - (√5)² = 9 - 5 = 4

Suma devine:

(3-√6)(3+√6)+(√3-1)(√3+1)-(3-√5)(3+√5) =

= 3 + 2 - 4

= 5 - 4

[tex]=\bf 1[/tex]

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Formule de calcul prescurtat:

[tex]\boxed{\boxed{\boldsymbol{(a \pm b)^{2} = a^{2} \pm 2ab + b^{2}}} \ \ \boxed{\boldsymbol{(a - b)(a + b) = a^{2} - b^{2}}}}\\[/tex]

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