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(87) Află numărul necunoscut: 10 [(42: 7+3×0) × 8-6]: 6=a: 7 100 [40-3 × (7:7 + 1 ×9)] × 6 = b × 5 [25+ (100- 2 x 4 x 10): 4]: (27 = c +c 35-d=19- (7+3 × 6): 5] x [3+(12-36: 9): 4] 6+e=3+ [(3 x 8: 6-6 × 0) + (30- 459) 5] × 3 1-2-5-[(10 x 10 : × 10 10 10) (7 × 7+ 50: 5)] : 10 r: [1+30: (8 x 4- 3 x 9)] = 7 y- [72: (20 - 2 x 6) + 15] = 68 zx[18-4 x (54: 6-48 : 8)] = 60 g+[40- (3 x 11 90 10+ 0 x 5) : 4] = 82 - - 31​