Dacă simplifici fiecare element obții:
[tex] (-3)^2 =9 \\ -\sqrt{\dfrac{1}{4}}=-\dfrac{1}{2} \\ (-2)^3 =-8 \\ \left(\dfrac{1}{2}\right)^{-1} =2 \\ \dfrac{-6}{-2} =3 \\ \sqrt{\dfrac{75}{48}}=\dfrac{5}{4} \\ \sqrt{5} =\sqrt{5} \\ \sqrt{0,09} =0,3 [/tex]
Mulțimea A este:
[tex] A=\left\{ 9, -\dfrac{1}{2},-8,2,3,\dfrac{5}{4}, \sqrt{5}, 0,3 \right\} [/tex]
Iar mulțimea [tex] \mathbb{N} [/tex] este:
[tex] \mathbb{N} =\{0,1,2,3,4,\ldots \} [/tex]
Deci:
[tex] A \cap \mathbb{N} =\{9,2,3\} \\ \tt A \cap \mathbb{N} =\left\{(-3)^2 , \left(\dfrac{1}{2}\right)^{-1}, \dfrac{-6}{-2} \right\} [/tex]
Răspuns: c)
