Explicație pas cu pas:
[tex]a) \: \frac{x}{3 \sqrt{2} } = \frac{ \sqrt{6} }{6} = > x = \frac{3 \sqrt{2} \times \sqrt{6} }{6} = \frac{3 \sqrt{12} }{6} {}^{(3} = \frac{ \sqrt{12} }{2} = \frac{2 \sqrt{3} }{2} {}^{(2} = \sqrt{3} \\ \\ b) \: \frac{x}{ \sqrt{3} } + \frac{2}{ \sqrt{6} } = \frac{ \sqrt{2} }{ \sqrt{3} } \\ \frac{x}{ \sqrt{3} } = {}^{ \sqrt{2} )} \frac{ \sqrt{2} }{ \sqrt{3} } - \frac{2}{ \sqrt{6} } \\ \frac{x}{ \sqrt{3} } = \frac{2}{ \sqrt{6} } - \frac{2}{ \sqrt{6} } \\ \frac{x}{ \sqrt{3} } = \frac{0}{ \sqrt{6} } \\ \frac{x}{ \sqrt{3} } = 0 = > x = \frac{ \sqrt{3} \times 0 }{1} = 0 [/tex]
Succes!
