[tex]0,8 = \dfrac{8}{10} = \dfrac{4}{5} \implies |x| = \sqrt{ \dfrac{4}{5}} = \dfrac{2\sqrt{5} }{5} \implies x = \pm \dfrac{2\sqrt{5} }{5}[/tex]
[tex]1,5 = \dfrac{15}{10} = \dfrac{3}{2} \implies |x| = \sqrt{ \dfrac{3}{2}} = \dfrac{\sqrt{6} }{2} \implies x = \pm \dfrac{\sqrt{6} }{2}[/tex]
[tex]x^{2} = -0,1 < 0 \implies x \not\in \Bbb{R}[/tex]
[tex]0,6 = \dfrac{6}{10} = \dfrac{3}{5} \implies |x| = \sqrt{ \dfrac{3}{5}} = \dfrac{\sqrt{15} }{5} \implies x = \pm \dfrac{\sqrt{15} }{5}[/tex]
